Code Bot compiler. 在线编译器 C. This code calculates the result of raising an integer 'a' to the power of 'b' (a^b) using a custom function 'f'. It handles the special case where 'b' is 0 by directly returning 1.

在线编译器 C

#include <stdio.h> int f(int a, int b) { int m = 1; for (int i = 0; i < b; i++) { m = m * a; } return (m); } int main() { int a, b; scanf("%d %d", &a, &b); int f(int a, int b); if (b == 0) { printf("%d", 1); } else { printf("%d", f(a, b)); } return 0; }

1) This code calculates the result of raising an integer 'a' to the power of 'b' (a^b) using a custom function 'f'. It handles the special case where 'b' is 0 by directly returning 1.

2) Hints:
- The function 'f' uses a loop to multiply 'a' by itself 'b' times. Think about how this relates to exponentiation.
- Notice how the main function checks if 'b' is 0 before calling 'f' - why is this special case needed?